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The square root of $64$ is $$
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$7x-12=8+\sqrt{4x^2}$
Learn how to solve problems step by step online. Solve the equation with radicals 7x-12=64^1/2+(4x^2)^1/2. The square root of 64 is . Move the term with the square root to the left side of the equation, and all other terms to the right side. Remember to change the signs of each term. Add 8 and 12. Multiply both sides of the equation by -1.