# Step-by-step Solution

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## Step-by-step explanation

Problem to solve:

$\left(x+2\right)\left(x-2\right)\left(x+2\right)$

Learn how to solve special products problems step by step online.

$\left(x^2-4\right)\left(x+2\right)$

Learn how to solve special products problems step by step online. Solve the product (x+2)(x-2)*(x+2). The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2, where:<ul><li>The first term (a) is x.</li><li>The second term (b) is 2.</li></ul>Then:. We can multiply the polynomials \left(x^2-4\right)\left(x+2\right) by using the FOIL method. The acronym F O I L stands for multiplying the terms in each bracket in the following order: First by First (F\times F), Outer by Outer (O\times O), Inner by Inner (I\times I), Last by Last (L\times L):<ul><li>(F\times F) is (x^2)(x)</li><li>(O\times O) is (x^2)(2)</li><li>(I\times I) is (-4)(x)</li><li>(L\times L) is (-4)(2)</li></ul><p class='exp-text'>Then, combine the four terms in a sum: (F\times F) + (O\times O) + (I\times I) + (L\times L):</p>. Multiply -4 times 2. When multiplying exponents with same base you can add the exponents.

$x^{3}+2x^2-4x-8$

### Problem Analysis

$\left(x+2\right)\left(x-2\right)\left(x+2\right)$

Special products

~ 0.04 seconds