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\frac{\frac{}{\sqrt{x x^2-2x+6}-\sqrt{x^2+2x+6}}}{x^2-4x+3}

Solve (/((-2x+6+xx^2)^0.5-1(2x+6+x^2)^0.5))/(-4x+3+x^2)

Answer

$\frac{}{\left(\sqrt{6-2x+x^{3}}-\sqrt{\left(1+x\right)^2+5}\right)\left(x-1\right)\left(x-3\right)}$

Step-by-step explanation

Problem

$\frac{\frac{}{\sqrt{x x^2-2x+6}-\sqrt{x^2+2x+6}}}{x^2-4x+3}$
1

When multiplying exponents with same base you can add the exponents

$\frac{\frac{}{\sqrt{6-2x+x^{3}}-\sqrt{6+2x+x^2}}}{3-4x+x^2}$

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Answer

$\frac{}{\left(\sqrt{6-2x+x^{3}}-\sqrt{\left(1+x\right)^2+5}\right)\left(x-1\right)\left(x-3\right)}$