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16x^2+10x-9=0

Solve the equation 10x-9+16x^2=0

Answer

$x_1=0.5,\:x_2=-1.125$

Step-by-step explanation

Problem

$16x^2+10x-9=0$
1

To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where $a=16$, $b=10$ and $c=-9$

$x =\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

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Answer

$x_1=0.5,\:x_2=-1.125$