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Find the integral $\int\frac{4y^2-8}{y^3+2y^2}dy$

Step-by-step Solution

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Solving: $\int\frac{4y^2-8}{y^3+2y^2}dy$

Final Answer

$\frac{4}{y}+2\ln\left(y+2\right)+2\ln\left(y\right)+C_0$
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Step-by-step Solution

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Rewrite the expression $\frac{4y^2-8}{y^3+2y^2}$ inside the integral in factored form

$\int\frac{4y^2-8}{y^2\left(y+2\right)}dy$

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$\int\frac{4y^2-8}{y^2\left(y+2\right)}dy$

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Learn how to solve problems step by step online. Find the integral int((4y^2-8)/(y^3+2y^2))dy. Rewrite the expression \frac{4y^2-8}{y^3+2y^2} inside the integral in factored form. Rewrite the fraction \frac{4y^2-8}{y^2\left(y+2\right)} in 3 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C. The first step is to multiply both sides of the equation from the previous step by y^2\left(y+2\right). Multiplying polynomials.

Final Answer

$\frac{4}{y}+2\ln\left(y+2\right)+2\ln\left(y\right)+C_0$

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Function Plot

Plotting: $\frac{4}{y}+2\ln\left(y+2\right)+2\ln\left(y\right)+C_0$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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