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Any expression multiplied by $1$ is equal to itself
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$\lim_{x\to-1}\left(\frac{2x^2-x-3}{x^3+x^2+6x+5}\right)$
Learn how to solve limits by direct substitution problems step by step online. Find the limit (x)->(-1)lim((2x^2-x+-3)/(x^3+1x^26x+5)). Any expression multiplied by 1 is equal to itself. Evaluate the limit \lim_{x\to-1}\left(\frac{2x^2-x-3}{x^3+x^2+6x+5}\right) by replacing all occurrences of x by -1. Subtract the values 5 and -6. Subtract the values 1 and -3.