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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=9$, $b=18$ and $c=17$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
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$x=\frac{-18\pm \sqrt{18^2-4\cdot 9\cdot 17}}{2\cdot 9}$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 9x^2+18x+17=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=9, b=18 and c=17. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Calculate the power \sqrt{-288} using complex numbers.