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Rewrite the integrand $\left(2x^3-1\right)\left(x^2+5\right)$ in expanded form
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$\int_{-3}^{3}\left(2x^{5}+10x^3-x^2-5\right)dx$
Learn how to solve problems step by step online. Integrate the function (2x^3-1)(x^2+5) from -3 to 3. Rewrite the integrand \left(2x^3-1\right)\left(x^2+5\right) in expanded form. Expand the integral \int_{-3}^{3}\left(2x^{5}+10x^3-x^2-5\right)dx into 4 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{-3}^{3}2x^{5}dx results in: 0. The integral \int_{-3}^{3}10x^3dx results in: 0.