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# Solve the differential equation $y^{\prime}\cos\left(x\right)+y\sin\left(x\right)=1$

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##  Final answer to the problem

$y\cos\left(x\right)^{-1}=\ln\left|\frac{\tan\left(\frac{x}{2}\right)-1}{\tan\left(\frac{x}{2}\right)+1}\right|+\frac{-2\tan\left(\frac{x}{2}\right)}{\tan\left(\frac{x}{2}\right)^{2}-1}+2\ln\left|\frac{\tan\left(\frac{x}{2}\right)+1}{\sqrt{\tan\left(\frac{x}{2}\right)^{2}-1}}\right|+C_0$
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##  Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Exact Differential Equation
• Linear Differential Equation
• Separable Differential Equation
• Homogeneous Differential Equation
• Integrate by partial fractions
• Product of Binomials with Common Term
• FOIL Method
• Integrate by substitution
• Integrate by parts
Can't find a method? Tell us so we can add it.
1

Rewrite the differential equation using Leibniz notation

$\frac{dy}{dx}\cos\left(x\right)+y\sin\left(x\right)=1$

Learn how to solve problems step by step online.

$\frac{dy}{dx}\cos\left(x\right)+y\sin\left(x\right)=1$

Learn how to solve problems step by step online. Solve the differential equation cos(x)y^'+ysin(x)=1. Rewrite the differential equation using Leibniz notation. Divide all the terms of the differential equation by \cos\left(x\right). Simplifying. We can identify that the differential equation has the form: \frac{dy}{dx} + P(x)\cdot y(x) = Q(x), so we can classify it as a linear first order differential equation, where P(x)=\frac{\sin\left(x\right)}{\cos\left(x\right)} and Q(x)=\frac{1}{\cos\left(x\right)}. In order to solve the differential equation, the first step is to find the integrating factor \mu(x).

##  Final answer to the problem

$y\cos\left(x\right)^{-1}=\ln\left|\frac{\tan\left(\frac{x}{2}\right)-1}{\tan\left(\frac{x}{2}\right)+1}\right|+\frac{-2\tan\left(\frac{x}{2}\right)}{\tan\left(\frac{x}{2}\right)^{2}-1}+2\ln\left|\frac{\tan\left(\frac{x}{2}\right)+1}{\sqrt{\tan\left(\frac{x}{2}\right)^{2}-1}}\right|+C_0$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

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0
a
b
c
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f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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