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Solve the trigonometric integral $\int\frac{\sin\left(x\right)^3}{\cos\left(x\right)}dx$

Step-by-step Solution

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Final Answer

$-\ln\left(\cos\left(x\right)\right)+\frac{1}{2}\cos\left(x\right)^2+C_0$
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Step-by-step Solution

Specify the solving method

1

Rewrite the trigonometric expression $\frac{\sin\left(x\right)^3}{\cos\left(x\right)}$ inside the integral

$\int\frac{\left(1-\cos\left(x\right)^2\right)\sin\left(x\right)}{\cos\left(x\right)}dx$
2

We can solve the integral $\int\frac{\left(1-\cos\left(x\right)^2\right)\sin\left(x\right)}{\cos\left(x\right)}dx$ by applying integration by substitution method (also called U-Substitution). First, we must identify a section within the integral with a new variable (let's call it $u$), which when substituted makes the integral easier. We see that $\cos\left(x\right)$ it's a good candidate for substitution. Let's define a variable $u$ and assign it to the choosen part

$u=\cos\left(x\right)$
3

Now, in order to rewrite $dx$ in terms of $du$, we need to find the derivative of $u$. We need to calculate $du$, we can do that by deriving the equation above

$du=-\sin\left(x\right)dx$
4

Isolate $dx$ in the previous equation

$\frac{du}{-\sin\left(x\right)}=dx$
5

Substituting $u$ and $dx$ in the integral and simplify

$-\int\frac{1-u^2}{u}du$
6

Expand the fraction $\frac{1-u^2}{u}$ into $2$ simpler fractions with common denominator $u$

$-\int\left(\frac{1}{u}+\frac{-u^2}{u}\right)du$
7

Simplify the resulting fractions

$-\int\left(\frac{1}{u}-u\right)du$
8

Expand the integral $\int\left(\frac{1}{u}-u\right)du$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately

$-\int\frac{1}{u}du-\int-udu$
9

The integral $-\int\frac{1}{u}du$ results in: $-\ln\left(\cos\left(x\right)\right)$

$-\ln\left(\cos\left(x\right)\right)$
10

The integral $-\int-udu$ results in: $\frac{1}{2}\cos\left(x\right)^2$

$\frac{1}{2}\cos\left(x\right)^2$
11

Gather the results of all integrals

$-\ln\left(\cos\left(x\right)\right)+\frac{1}{2}\cos\left(x\right)^2$
12

As the integral that we are solving is an indefinite integral, when we finish integrating we must add the constant of integration $C$

$-\ln\left(\cos\left(x\right)\right)+\frac{1}{2}\cos\left(x\right)^2+C_0$

Final Answer

$-\ln\left(\cos\left(x\right)\right)+\frac{1}{2}\cos\left(x\right)^2+C_0$

Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Solve integral of ((sinx^3)/cosx)dx using basic integralsSolve integral of ((sinx^3)/cosx)dx using u-substitutionSolve integral of ((sinx^3)/cosx)dx using integration by partsSolve integral of ((sinx^3)/cosx)dx using weierstrass substitution

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Function Plot

Plotting: $-\ln\left(\cos\left(x\right)\right)+\frac{1}{2}\cos\left(x\right)^2+C_0$

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0
a
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g
m
n
u
v
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x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Differential Equations

A differential equation is a mathematical equation that relates some function with its derivatives.

Used Formulas

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