$\left(4b+c\right)^2$
$n^{\left(3\right)}-4n^{\left(2\right)}+4n$
$\sqrt{\left(\frac{x-5}{x^8+3}\right)}$
$10+6-10\:times\:9$
$\frac{\left(x^2+19x-47\right)}{\left(4x^2+2x+18\right)}$
$x^2+6x=40$
$\left(h-6\right)\left(h+6\right)=0$
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