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Moving the term $-10$ to the other side of the inequation with opposite sign
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$y^2+3y\leq 0+10$
Learn how to solve problems step by step online. Solve the inequality y^2+3y+-10<=0. Moving the term -10 to the other side of the inequation with opposite sign. Add the values 0 and 10. Factor the polynomial y^2+3y. Add and subtract \left(\frac{b}{2}\right)^2, replacing b by it's value 3. Now, we can factor y^2+3x+\frac{9}{4} as a squared binomial of the form \left(x+\frac{b}{2}\right)^2.