$\frac{1}{\left(\left(x+a\right)\left(x+b\right)\right)}$
$\left(x\:-\:\frac{1}{3}\right)^2$
$\infty-31434$
$x^2+9x+12$
$\left(-1\right)^{17}.\left(-2\right)^5$
$\left(6x+4y\right)-y$
$\sqrt[3]{54x^3}y^2z^5$
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