$\int^3\sqrt{20+3x^3}\left(x^2\right)dx$
$3x^2-48x+256=0$
$\frac{x^3+5x^2-3x+1}{x+2}$
$\frac{dy}{dx}\left(y=\sin\left(2x\right)^{-1}\right)$
$f\left(x\right)=\left(3x-5\right)^5$
$x^2=-10x-16$
$\frac{d^3}{dx^3}\left(-\frac{1}{24}x^{-4}-\frac{3}{20}x-x^3+\frac{5}{18}\right)$
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