$a^2+b^2=146$
$\frac{dx}{dt}+2x=cos\left(5t\right)$
$\frac{\left(3x+x^2\right)}{1}^2$
$\tan\left(x+y\right)=\frac{\tan\left(x\right)+\tan\left(y\right)}{1-\tan\left(x\right)\cdot\tan\left(y\right)}$
$\frac{-3264}{-51}$
$20-\frac{5000}{x^2}$
$x+5<1$
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