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Integrate the function $2x-x^2-x^2$ from $\frac{1}{4}$ to $\frac{3}{4}$

Step-by-step Solution

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Final Answer

$\frac{11}{48}$
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Step-by-step Solution

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Simplify the expression inside the integral

$\int_{\frac{1}{4}}^{\frac{3}{4}}2xdx+\int_{\frac{1}{4}}^{\frac{3}{4}}-2x^2dx$

Learn how to solve definite integrals problems step by step online.

$\int_{\frac{1}{4}}^{\frac{3}{4}}2xdx+\int_{\frac{1}{4}}^{\frac{3}{4}}-2x^2dx$

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Learn how to solve definite integrals problems step by step online. Integrate the function 2x-x^2-x^2 from 1/4 to 3/4. Simplify the expression inside the integral. The integral \int_{\frac{1}{4}}^{\frac{3}{4}}2xdx results in: \frac{1}{2}. The integral \int_{\frac{1}{4}}^{\frac{3}{4}}-2x^2dx results in: -\frac{13}{48}. Gather the results of all integrals.

Final Answer

$\frac{11}{48}$

Exact Numeric Answer

$0.2292$

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Function Plot

Plotting: $2x-x^2-x^2$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Definite Integrals

Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b

Used Formulas

2. See formulas

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