# Step-by-step Solution

## Solve the equation (x^2-3x)/2-5=(x-20)/4

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### Videos

$x_1=1.7913,\:x_2=-2.7913$

## Step-by-step explanation

Problem to solve:

$\frac{x^2-3x}{2}-5=\frac{x-20}{4}$
1

Grouping terms

$\frac{x^2-3x}{2}-5-\left(\frac{x-20}{4}\right)=0$
2

To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where $a=1$, $b=1$ and $c=-5$

$x =\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x_1=1.7913,\:x_2=-2.7913$
$\frac{x^2-3x}{2}-5=\frac{x-20}{4}$

Product rule

~ 1.1 seconds

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