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\frac{x^2-3x}{2}-5=\frac{x-20}{4}

Solve the equation (x^2-3x)/2-5=(x-20)/4

Answer

$x_1=1.7913,\:x_2=-2.7913$

Step-by-step explanation

Problem

$\frac{x^2-3x}{2}-5=\frac{x-20}{4}$
1

Grouping terms

$-\frac{x-20}{4}-5+\frac{x^2-3x}{2}=0$

Unlock this step-by-step solution!

Answer

$x_1=1.7913,\:x_2=-2.7913$