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Solve the equation (x^2-3x)/2-5=(x-20)/4

\frac{x^2-3x}{2}-5=\frac{x-20}{4}

Step by step solution

Problem

$\frac{x^2-3x}{2}-5=\frac{x-20}{4}$

Show full step-by-step solution

Answer

$x_1=1.7913,\:x_2=-2.7913$

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$\frac{x^2-3x}{2}-5=\frac{x-20}{4}$

Main topic:

Quadratic formula

Used formulas:

0

Time to solve it:

0.26 seconds