$\left(x^4-16\right)\cdot\left(x^4-2\cdot x^2+1\right)$
$\left(5+y^2\right)^3$
$16\:-\:4\:x^2$
$\left(xy-2\right)\left(xy+2\right)$
$3x-4<2x+5$
$x+3<5$
$x^2-8x+36=0$
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