$3x^4+x^2-4x$
$\frac{g+10}{4}=3$
$2+6+7$
$y=\frac{\left(x^3-8\right)^{\frac{1}{3}}\left(x^2+1\right)^{\frac{1}{2}}}{2x^6+7x-4}$
$\left(2+3x^2\right)^4$
$-6c+2c-4+8$
$20-3-15+22+30$
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