$\left(2z-4y\right)^3$
$16b^2-64$
$\int\frac{1}{y^3\sqrt{y^2-9}}dy$
$9\cdot2\cdot\left(-1\right)$
$9\left(-44444-3\right)$
$6k-2k$
$4+2-\left(-3\right)+3$
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