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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=8$, $b=-16$ and $c=24$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
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$t=\frac{16\pm \sqrt{{\left(-16\right)}^2-4\cdot 8\cdot 24}}{2\cdot 8}$
Learn how to solve problems step by step online. Solve the quadratic equation 8t^2-16t+24=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=8, b=-16 and c=24. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Calculate the power \sqrt{-512} using complex numbers.