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Find the derivative of -2y+3x^3+y^3=4x+1

\frac{d}{dx}\left(y^3-2y+3x^3=4x+1\right)

Step by step solution

Problem

$\frac{d}{dx}\left(y^3-2y+3x^3=4x+1\right)$

Show full step-by-step solution

Answer

$\frac{d}{dx}\left(3x^3-2y+y^3\right)=\frac{d}{dx}\left(1+4x\right)$
$\frac{d}{dx}\left(y^3-2y+3x^3=4x+1\right)$

Main topic:

Differential calculus

Used formulas:

0

Time to solve it:

0.22 seconds