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\frac{d}{dx}\left(y^3-2y+3x^3=4x+1\right)

Derive the function -2y+3x^3+y^3=4x+1 with respect to x

Answer

$9x^{2}=4$

Step-by-step explanation

Problem

$\frac{d}{dx}\left(y^3-2y+3x^3=4x+1\right)$
1

Apply implicit differentiation by taking the derivative of both sides of the equation with respect to the differentiation variable

$\frac{d}{dx}\left(3x^3-2y+y^3\right)=\frac{d}{dx}\left(1+4x\right)$

Unlock this step-by-step solution!

Answer

$9x^{2}=4$

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$\frac{d}{dx}\left(y^3-2y+3x^3=4x+1\right)$

Main topic:

Differential calculus

Used formulas:

4. See formulas

Time to solve it:

~ 0.23 seconds