Find the integral $\int3e^y\cos\left(e^y\right)dy$

Step-by-step Solution

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Final answer to the problem

$3\sin\left(e^y\right)+C_0$
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Step-by-step Solution

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  • Integrate by partial fractions
  • Integrate by substitution
  • Integrate by parts
  • Integrate using tabular integration
  • Integrate by trigonometric substitution
  • Weierstrass Substitution
  • Integrate using trigonometric identities
  • Integrate using basic integrals
  • Product of Binomials with Common Term
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1

The integral of a function times a constant ($3$) is equal to the constant times the integral of the function

$3\int e^y\cos\left(e^y\right)dy$

Learn how to solve differential equations problems step by step online.

$3\int e^y\cos\left(e^y\right)dy$

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Learn how to solve differential equations problems step by step online. Find the integral int(3e^ycos(e^y))dy. The integral of a function times a constant (3) is equal to the constant times the integral of the function. We can solve the integral \int e^y\cos\left(e^y\right)dy by applying integration by substitution method (also called U-Substitution). First, we must identify a section within the integral with a new variable (let's call it u), which when substituted makes the integral easier. We see that e^y it's a good candidate for substitution. Let's define a variable u and assign it to the choosen part. Now, in order to rewrite dy in terms of du, we need to find the derivative of u. We need to calculate du, we can do that by deriving the equation above. Isolate dy in the previous equation.

Final answer to the problem

$3\sin\left(e^y\right)+C_0$

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Function Plot

Plotting: $3\sin\left(e^y\right)+C_0$

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3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Differential Equations

A differential equation is a mathematical equation that relates some function with its derivatives.

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