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# Multiply $-8\left|3\cdot \left(4- 6- 9+7+1\right)\cdot \left(2- 5- 7+6- 5\right)+50\right|$

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##  Final answer to the problem

$-8\left|131\right|$
Got another answer? Verify it here!

##  Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Write in simplest form
• Prime Factor Decomposition
• Solve by quadratic formula (general formula)
• Find the derivative using the definition
• Simplify
• Find the integral
• Find the derivative
• Factor
• Factor by completing the square
Can't find a method? Tell us so we can add it.
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Add the values $4$ and $7$

$-8\left|3\cdot \left(11- 6- 9+1\right)\cdot \left(2- 5- 7+6- 5\right)+50\right|$

Learn how to solve multiplication of numbers problems step by step online.

$-8\left|3\cdot \left(11- 6- 9+1\right)\cdot \left(2- 5- 7+6- 5\right)+50\right|$

Learn how to solve multiplication of numbers problems step by step online. Multiply -8abs(3(4-*6-*9+7+1)(2-*5-*7+6-*5)+50). Add the values 4 and 7. Add the values 11 and 1. Add the values 2 and 6. Multiply -1 times 6.

##  Final answer to the problem

$-8\left|131\right|$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SnapXam A2

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

###  Main Topic: Multiplication of Numbers

The terms a and b are called factors and the result, c, is the product.