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The cube of a binomial (sum) is equal to the cube of the first term, plus three times the square of the first by the second, plus three times the first by the square of the second, plus the cube of the second term. In other words: $(a+b)^3=a^3+3a^2b+3ab^2+b^3 = (x)^3+3(x)^2(2)+3(x)(2)^2+(2)^3 =$
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$\frac{x^2x^3+3\cdot 2x^2+3\cdot 2^2x+2^3\sin\left(x\right)^2}{\left(2x+1\right)^5\left(3x+2\right)}$
Learn how to solve simplification of algebraic fractions problems step by step online. Simplify the expression (x^2(x+2)^3sin(x)^2)/((2x+1)^5(3x+2)). The cube of a binomial (sum) is equal to the cube of the first term, plus three times the square of the first by the second, plus three times the first by the square of the second, plus the cube of the second term. In other words: (a+b)^3=a^3+3a^2b+3ab^2+b^3 = (x)^3+3(x)^2(2)+3(x)(2)^2+(2)^3 =. Multiply 3 times 2. Calculate the power 2^2. Multiply 3 times 4.