Step-by-step Solution

Prove the trigonometric identity $\frac{\left(\sin\left(x\right)+\cos\left(x\right)\right)^2}{\sin\left(x\right)^2-\cos\left(x\right)^2}=\frac{\sin\left(x\right)^2-\cos\left(x\right)^2}{\left(\sin\left(x\right)-\cos\left(x\right)\right)^2}$

Go!
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Step-by-step explanation

Problem to solve:

$\frac{\left(sin\left(x\right)+cos\left(x\right)\right)^2}{sin^2\left(x\right)-cos^2\left(x\right)}=\frac{sin^2\left(x\right)-cos^2\left(x\right)}{\left(sin\left(x\right)-cos\left(x\right)\right)^2}$

Final Answer

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Problem Analysis

$\frac{\left(sin\left(x\right)+cos\left(x\right)\right)^2}{sin^2\left(x\right)-cos^2\left(x\right)}=\frac{sin^2\left(x\right)-cos^2\left(x\right)}{\left(sin\left(x\right)-cos\left(x\right)\right)^2}$

Related formulas:

1. See formulas

Time to solve it:

~ 0.3 seconds