$\lim_{x\to1}\left(x+3\right)\left(x+5\right)$
$6x^2-4x+6$
$2x^2-6x+4=0$
$\left(7x+2\right)\left(7x-3\right)$
$3x=-9$
$\int\frac{1}{100+x^2}dx$
$\lim_{x\to\infty}\left(\frac{3x^2-5}{e^x-1}\right)$
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