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\frac{2+x}{3}-\frac{2\left(x-1\right)}{7}\geq \frac{-5x+7}{3}-\frac{3\left(3x+1\right)}{7}

Solve the inequality (2+x)/3-1(2(x-1))/7%(-5x+7)/3-1(3(3x+1))/7

Answer

$\frac{62}{21}x+\frac{20+x}{21}\geq \frac{40}{21}$

Step-by-step explanation

Problem

$\frac{2+x}{3}-\frac{2\left(x-1\right)}{7}\geq \frac{-5x+7}{3}-\frac{3\left(3x+1\right)}{7}$
1

Multiplying polynomials $2$ and $x+-1$

$\frac{x+2}{3}-\frac{2x-1\cdot 2}{7}\geq \frac{7-5x}{3}-\frac{1\cdot 3+3\cdot 3x}{7}$

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Answer

$\frac{62}{21}x+\frac{20+x}{21}\geq \frac{40}{21}$

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