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{3x-2x-10\left(x-3\right)}\geq {6\left(x-3\right)+9}

Solve the inequality -2x-10(x-3)+3x%6(x-3)+9

Answer

$b\cdot x+a\cdot x-16x\geq -9$

Step-by-step explanation

Problem

${3x-2x-10\left(x-3\right)}\geq {6\left(x-3\right)+9}$
1

Multiply $\left([a]+[b]\right)$ by $-1$

$-2x+3x-10x\geq 9-18+6x$

Unlock this step-by-step solution!

Answer

$b\cdot x+a\cdot x-16x\geq -9$

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