Simplify $\left(\left(1-e^{-x}\right)^2\right)^{2x}$ using the power of a power property: $\left(a^m\right)^n=a^{m\cdot n}$. In the expression, $m$ equals $2$ and $n$ equals $2x$
$\left(1-e^{-x}\right)^{2\cdot 2x}$
2
Multiply $2$ times $2$
$\left(1-e^{-x}\right)^{4x}$
Final Answer
$\left(1-e^{-x}\right)^{4x}$
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Special products is the multiplication of algebraic expressions that follow certain rules and patterns, so you can predict the result without necessarily doing the multiplication.