$y\frac{dx}{dy}=\frac{x}{4}$
$\frac{27}{7},\pi,\sqrt{14}\sqrt{16},27.4,\:\frac{65}{13}$
$\int\left(\frac{20x^3}{\sqrt{25-25x^8}}\right)dx$
$3x^2-2x+6$
$\left(2\cdot16\right)-42+\left(9\cdot8\right)-4+3$
$2tanxcot^2x$
$4x^2-20x-24y=-97$
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