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Step-by-step Solution

Integral of $\frac{6}{8x-1}$ with respect to x

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Answer

$\frac{3}{4}\ln\left|8x-1\right|+C_0$

Step-by-step explanation

Problem to solve:

$\int\frac{6}{8x-1}dx$
1

Take the constant out of the integral

$6\int\frac{1}{-1+8x}dx$
2

Apply the formula: $\int\frac{n}{ax+b}dx$$=\frac{n}{a}\ln\left|ax+b\right|$, where $a=8$, $b=-1$ and $n=1$

$\frac{3}{4}\ln\left|8x-1\right|$

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Answer

$\frac{3}{4}\ln\left|8x-1\right|+C_0$
$\int\frac{6}{8x-1}dx$

Main topic:

Integrals of Rational Functions

Used formulas:

5. See formulas

Time to solve it:

~ 0.77 seconds

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