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\left(a+3b\right)\left(a-3b\right)

Solve (a+3b)(a-3b)

Answer

$a^2-9b^2$

Step-by-step explanation

Problem

$\left(a+3b\right)\left(a-3b\right)$
1

By multiplying conjugated binomials you get a difference of squares: $(a+b)(a-b)=a^2-b^2$

$a^2-\left(-3b\right)^2$

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Answer

$a^2-9b^2$