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Step-by-step Solution

Solve the product (a+3b)(a-3b)

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Answer

$a^2-9b^2$

Step-by-step explanation

Problem to solve:

$\left(a+3b\right)\left(a-3b\right)$
1

The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: $(a+b)(a-b)=a^2-b^2$, where:

  • The first term ($a$) is $a$.
  • The second term ($b$) is $3b$.
Then:

$a^2-\left(3b\right)^2$
2

The power of a product is equal to the product of it's factors raised to the same power

$a^2-9b^2$

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Answer

$a^2-9b^2$
$\left(a+3b\right)\left(a-3b\right)$

Main topic:

Factor by difference of squares

Time to solve it:

~ 0.43 seconds