Integrate the function $\frac{x^2-4}{x^2-16}$ from $-3$ to $3$

Learn how to solve definite integrals problems step by step online.

$\begin{array}{l}\phantom{\phantom{;}x^{2}-16;}{\phantom{;}1\phantom{;}\phantom{;}}\\\phantom{;}x^{2}-16\overline{\smash{)}\phantom{;}x^{2}\phantom{-;x^n}-4\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x^{2}-16;}\underline{-x^{2}\phantom{-;x^n}+16\phantom{;}\phantom{;}}\\\phantom{-x^{2}+16\phantom{;}\phantom{;};}\phantom{;}12\phantom{;}\phantom{;}\\\end{array}$

Learn how to solve definite integrals problems step by step online. Integrate the function (x^2-4)/(x^2-16) from -3 to 3. Divide x^2-4 by x^2-16. Resulting polynomial. Expand the integral \int_{-3}^{3}\left(1+\frac{12}{x^2-16}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{-3}^{3}1dx results in: 6.