$x^4a^2-625a^6$
$\int\frac{x-3}{\left(x^2+4\right)\left(x-1\right)^2}dx$
$3x-4=5$
$\left(2x^{10}+3\right)^2$
$\frac{9^8-5^8}{9+5}$
$\frac{3}{4}\:=\:\frac{1}{4}\:$
$\lim_{x\to2}\frac{\left(x^3+2x^2-8x\right)}{\left(x^3-8\right)}$
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