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Rewrite the expression $\frac{6x}{x^3-8}$ inside the integral in factored form
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$\int\frac{6x}{\left(x-2\right)\left(x^2+2x+4\right)}dx$
Learn how to solve simplify trigonometric expressions problems step by step online. Find the integral int((6x)/(x^3-8))dx. Rewrite the expression \frac{6x}{x^3-8} inside the integral in factored form. Take out the constant 6 from the integral. Rewrite the fraction \frac{x}{\left(x-2\right)\left(x^2+2x+4\right)} in 2 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C. The first step is to multiply both sides of the equation from the previous step by \left(x-2\right)\left(x^2+2x+4\right).