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$\lim_{x\to\frac{\pi}{2}}\left(\frac{\ln\left(\sin\left(x\right)\right)}{\left(\pi -2x\right)^2}\right)$
Learn how to solve limits by direct substitution problems step by step online. Find the limit (x)->(pi/2)lim(ln(sin(x))/((pi-2x)^2)). Simplifying. Evaluate the limit \lim_{x\to\frac{\pi}{2}}\left(\frac{\ln\left(\sin\left(x\right)\right)}{\left(\pi -2x\right)^2}\right) by replacing all occurrences of x by 1.5708. Multiply -2 times \frac{\pi}{2}. Subtract the values \pi and -\pi .