Solve the inequality 1/(3x-7)%4/(3-2x)
Answer
$\frac{3-2x-43\left(x-\frac{7}{3}\right)}{3\left(x-\frac{7}{3}\right)3\left(1-\frac{2}{3}x\right)}\geq 0$
Step-by-step explanation
Problem to solve:
$\frac{1}{3x-7}\geq \frac{4}{3-2x}$
1
Subtract $\frac{4}{3-2x}$ from both sides
$\frac{1}{3x-7}+\frac{-4}{3-2x}\geq 0$
2
Unifying fractions
$\frac{3-2x-4\left(3x-7\right)}{\left(3x-7\right)\left(3-2x\right)}\geq 0$
Answer
$\frac{3-2x-43\left(x-\frac{7}{3}\right)}{3\left(x-\frac{7}{3}\right)3\left(1-\frac{2}{3}x\right)}\geq 0$