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\frac{1}{3x-7}\geq \frac{4}{3-2x}

Solve the inequality 1/(3x-7)%4/(3-2x)

Answer

$\frac{-4\left(3x-7\right)-2x+3}{3\left(3x-7\right)-2x\left(3x-7\right)}\geq 0$

Step-by-step explanation

Problem

$\frac{1}{3x-7}\geq \frac{4}{3-2x}$
1

Subtract $\frac{4}{3-2x}$ from both sides

$\frac{-4}{3-2x}+\frac{1}{3x-7}\geq 0$

Unlock this step-by-step solution!

Answer

$\frac{-4\left(3x-7\right)-2x+3}{3\left(3x-7\right)-2x\left(3x-7\right)}\geq 0$

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