Solve the inequality 1/(3x-7)%4/(3-2x)
Answer
$\frac{-4\left(3x-7\right)-2x+3}{3\left(3x-7\right)-2x\left(3x-7\right)}\geq 0$
Step-by-step explanation
Problem
$\frac{1}{3x-7}\geq \frac{4}{3-2x}$
1
Subtract $\frac{4}{3-2x}$ from both sides
$\frac{-4}{3-2x}+\frac{1}{3x-7}\geq 0$
Answer
$\frac{-4\left(3x-7\right)-2x+3}{3\left(3x-7\right)-2x\left(3x-7\right)}\geq 0$