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\frac{1}{3x-7}\geq \frac{4}{3-2x}

Solve the inequality 1/(3x-7)%4/(3-2x)

Answer

$\frac{3-2x-43\left(x-\frac{7}{3}\right)}{3\left(x-\frac{7}{3}\right)3\left(1-\frac{2}{3}x\right)}\geq 0$

Step-by-step explanation

Problem to solve:

$\frac{1}{3x-7}\geq \frac{4}{3-2x}$
1

Subtract $\frac{4}{3-2x}$ from both sides

$\frac{1}{3x-7}+\frac{-4}{3-2x}\geq 0$
2

Unifying fractions

$\frac{3-2x-4\left(3x-7\right)}{\left(3x-7\right)\left(3-2x\right)}\geq 0$

Unlock this step-by-step solution!

Answer

$\frac{3-2x-43\left(x-\frac{7}{3}\right)}{3\left(x-\frac{7}{3}\right)3\left(1-\frac{2}{3}x\right)}\geq 0$
$\frac{1}{3x-7}\geq \frac{4}{3-2x}$

Main topic:

Inequalities

Time to solve it:

~ 1.26 seconds

Related topics:


InequalitiesFactorization