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The integral of a function times a constant ($3$) is equal to the constant times the integral of the function
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$3\int y\sqrt{7-3y^2}dy$
Learn how to solve problems step by step online. Integrate int(3y(7-3y^2)^1/2)dy. The integral of a function times a constant (3) is equal to the constant times the integral of the function. First, factor the terms inside the radical by 3 for an easier handling. Taking the constant out of the radical. We can solve the integral 3\int\sqrt{3}y\sqrt{\frac{7}{3}-y^2}dy by applying integration method of trigonometric substitution using the substitution.