Final Answer
$8x^{4}+8x^{3}+8x^{2}+5x+5+\frac{4}{x-1}$
Got another answer? Verify it here!
Step-by-step Solution
Specify the solving method
1
Divide $8x^5-3x^2-1$ by $x-1$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}-1;}{\phantom{;}8x^{4}+8x^{3}+8x^{2}+5x\phantom{;}+5\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}-1\overline{\smash{)}\phantom{;}8x^{5}\phantom{-;x^n}\phantom{-;x^n}-3x^{2}\phantom{-;x^n}-1\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}-1;}\underline{-8x^{5}+8x^{4}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-8x^{5}+8x^{4};}\phantom{;}8x^{4}\phantom{-;x^n}-3x^{2}\phantom{-;x^n}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-1-;x^n;}\underline{-8x^{4}+8x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;-8x^{4}+8x^{3}-;x^n;}\phantom{;}8x^{3}-3x^{2}\phantom{-;x^n}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-1-;x^n-;x^n;}\underline{-8x^{3}+8x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;;-8x^{3}+8x^{2}-;x^n-;x^n;}\phantom{;}5x^{2}\phantom{-;x^n}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-1-;x^n-;x^n-;x^n;}\underline{-5x^{2}+5x\phantom{;}\phantom{-;x^n}}\\\phantom{;;;-5x^{2}+5x\phantom{;}-;x^n-;x^n-;x^n;}\phantom{;}5x\phantom{;}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-1-;x^n-;x^n-;x^n-;x^n;}\underline{-5x\phantom{;}+5\phantom{;}\phantom{;}}\\\phantom{;;;;-5x\phantom{;}+5\phantom{;}\phantom{;}-;x^n-;x^n-;x^n-;x^n;}\phantom{;}4\phantom{;}\phantom{;}\\\end{array}$
2
Resulting polynomial
$8x^{4}+8x^{3}+8x^{2}+5x+5+\frac{4}{x-1}$
Final Answer
$8x^{4}+8x^{3}+8x^{2}+5x+5+\frac{4}{x-1}$