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Express the numbers in the equation as logarithms of base $4$
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$\log_{4}\left(3x+4\right)=\log_{4}\left(4^{2}\right)$
Learn how to solve differential calculus problems step by step online. Solve the logarithmic equation log4(3*x+4)=2. Express the numbers in the equation as logarithms of base 4. Calculate the power 4^{2}. For two logarithms of the same base to be equal, their arguments must be equal. In other words, if \log(a)=\log(b) then a must equal b. We need to isolate the dependent variable x, we can do that by simultaneously subtracting 4 from both sides of the equation.