$\lim\:_{x\to\:0}\frac{\left(4x^3+8x+1\right)}{x}$
$2x^2+8x+6=0$
$\left(x+\frac{1}{x}\right)^2=36$
$\int\frac{x^5+2x^3-x}{x^4+10x^2+25}dx$
$\left(x+2y\right)^1^0$
$\frac{dy}{dx}=\frac{2+13x}{xy^2}$
$\left(\frac{3}{4}xyz\right)\left(-\frac{2}{5}x^4\right)$
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