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Solve the quadratic equation $x^2+3x+10=20$

Step-by-step Solution

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Final Answer

$x=2,\:x=-5$
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Step-by-step Solution

Problem to solve:

$x^2+3x+10=20$

Specify the solving method

1

Group the terms of the equation by moving the terms that have the variable $x$ to the left side, and those that do not have it to the right side

$x^2+3x=20-10$

Learn how to solve quadratic equations problems step by step online.

$x^2+3x=20-10$

Unlock the first 3 steps of this solution!

Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation x^2+3x+10=20. Group the terms of the equation by moving the terms that have the variable x to the left side, and those that do not have it to the right side. Subtract the values 20 and -10. Rewrite the equation. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=3 and c=-10. Then substitute the values of the coefficients of the equation in the quadratic formula:<ul><li>\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}</li></ul>.

Final Answer

$x=2,\:x=-5$
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Answer Assistant

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Got another answer? Verify it!

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

Useful tips on how to improve your answer:

$x^2+3x+10=20$

Main topic:

Quadratic equations

Used formulas:

1. See formulas

Time to solve it:

~ 0.07 s