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Step-by-step Solution

Solve $\frac{4}{\frac{3x^2-8x-16}{2x^2-9x+4}}$

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Answer

$\frac{4\left(4+x\left(2x-9\right)\right)}{-16+x\left(3x-8\right)}$

Step-by-step explanation

Problem to solve:

$\frac{4}{\frac{3x^2-8x-16}{2x^2-9x+4}}$
1

Simplifying the fraction

$4\left(\frac{2x^2-9x+4}{3x^2-8x-16}\right)$
2

Multiplying the fraction and term

$\frac{4\left(2x^2-9x+4\right)}{3x^2-8x-16}$

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Answer

$\frac{4\left(4+x\left(2x-9\right)\right)}{-16+x\left(3x-8\right)}$
$\frac{4}{\frac{3x^2-8x-16}{2x^2-9x+4}}$

Main topic:

Time to solve it:

~ 0.86 seconds

Related topics:


Factorization

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