$x\left(2x-\frac{1}{2x^2}\right)^8$
$3\tan^2x-4=-3$
$\int_0^{0.8}\left(\frac{x^2}{\sqrt{144-4x^2}}\right)dx$
$\left(2p-10\right)\left(2p-7\right)$
$\sqrt{121x^{10}y^{14}}$
$\int x^3\sqrt{a^3x^2-b^2}dx$
$x\:-\:2\:<=\:2x\:-5$
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