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Step-by-step Solution

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asin
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asinh
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Answer

$-\frac{8}{3}$

Step-by-step explanation

Problem to solve:

$\int_{0}^{2}\left(x^3-x^2-2x\right)dx$
1

The integral of a sum of two or more functions is equal to the sum of their integrals

$\int_{0}^{2} x^3dx+\int_{0}^{2}-x^2dx+\int_{0}^{2}-2xdx$
2

Take the constant out of the integral

$\int_{0}^{2} x^3dx-\int_{0}^{2} x^2dx+\int_{0}^{2}-2xdx$

Answer

$-\frac{8}{3}$

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$\int_{0}^{2}\left(x^3-x^2-2x\right)dx$

Main topic:

Integral calculus

~ 0.46 seconds