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Integrate the function $\frac{1}{\sqrt{9-x^2}}$ from 0 to $3$

Step-by-step Solution

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Final Answer

$\frac{\pi}{2}$
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Step-by-step Solution

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Apply the well-known integration formula: $\displaystyle\int\frac{1}{\sqrt{a^2-x^2}}dx = \arcsin\left(\frac{x}{a}\right)$

$\left[\arcsin\left(\frac{x}{\sqrt{9}}\right)\right]_{0}^{3}$

Learn how to solve definite integrals problems step by step online.

$\left[\arcsin\left(\frac{x}{\sqrt{9}}\right)\right]_{0}^{3}$

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Learn how to solve definite integrals problems step by step online. Integrate the function 1/((9-x^2)^1/2) from 0 to 3. Apply the well-known integration formula: \displaystyle\int\frac{1}{\sqrt{a^2-x^2}}dx = \arcsin\left(\frac{x}{a}\right). Calculate the power \sqrt{9}. Evaluate the definite integral. Simplify the expression inside the integral.

Final Answer

$\frac{\pi}{2}$

Exact Numeric Answer

$1.570796$

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Function Plot

Plotting: $\frac{1}{\sqrt{9-x^2}}$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Definite Integrals

Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b

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