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$\int\sec\left(ti\right)^2dt+\int\frac{j}{1+t^2}dt$
Learn how to solve problems step by step online. Find the integral int(sec(ti)^2+1/(1+t^2)j)dt. Simplify the expression inside the integral. The integral \int\sec\left(ti\right)^2dt results in: \ln\left(\frac{t-1}{t+1}\right)+\frac{-2t}{t^{2}-1}+2\ln\left(\frac{t}{\sqrt{t^{2}-1}}+\frac{1}{\sqrt{t^{2}-1}}\right). Gather the results of all integrals. The integral \int\frac{j}{1+t^2}dt results in: j\arctan\left(t\right).