$y^2+y+.25$
$x+1x+4\ge x+6x+3$
$\int\left(x\left(1-x\right)^2\right)dx$
$9v+18$
$2+\frac{1}{6}a=-4$
$\int\left(t^2+1\right)\left(t^3+3t\right)^4dt$
$z^2-18z$
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