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\frac{d^2}{dx^2}\left(y\right)+\left(x^2-2x+2\right)\cdot y\cdot\frac{}{}=0

Find the higher order derivative of y

Answer

$2y-2y\cdot x+x^2y=0$

Step-by-step explanation

Problem

$\frac{d^2}{dx^2}\left(y\right)+\left(x^2-2x+2\right)\cdot y\cdot\frac{}{}=0$
1

Simplifying the fraction by $$

$1y\left(2-2x+x^2\right)+\frac{d^2}{dx^2}\left(y\right)=0$

Unlock this step-by-step solution!

Answer

$2y-2y\cdot x+x^2y=0$

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$\frac{d^2}{dx^2}\left(y\right)+\left(x^2-2x+2\right)\cdot y\cdot\frac{}{}=0$

Main topic:

Differential calculus

Used formulas:

1. See formulas

Time to solve it:

~ 0.31 seconds