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Find the higher order derivative of y

\frac{d^2}{dx^2}\left(y\right)+\left(x^2-2x+2\right)\cdot y\cdot\frac{}{}=0

Step by step solution

Problem

$\frac{d^2}{dx^2}\left(y\right)+\left(x^2-2x+2\right)\cdot y\cdot\frac{}{}=0$

Show full step-by-step solution

Answer

$y\left(2-2x+x^2\right)=0$
$\frac{d^2}{dx^2}\left(y\right)+\left(x^2-2x+2\right)\cdot y\cdot\frac{}{}=0$

Main topic:

Differential calculus

Used formulas:

1. See formulas

Time to solve it:

0.24 seconds